Integrand size = 41, antiderivative size = 225 \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=a^4 C x+\frac {a^4 (28 A+35 B+48 C) \text {arctanh}(\sin (c+d x))}{8 d}+\frac {a^4 (28 A+35 B+40 C) \tan (c+d x)}{8 d}+\frac {(28 A+35 B+32 C) \left (a^4+a^4 \cos (c+d x)\right ) \sec (c+d x) \tan (c+d x)}{24 d}+\frac {(28 A+35 B+20 C) \left (a^2+a^2 \cos (c+d x)\right )^2 \sec ^2(c+d x) \tan (c+d x)}{60 d}+\frac {a (4 A+5 B) (a+a \cos (c+d x))^3 \sec ^3(c+d x) \tan (c+d x)}{20 d}+\frac {A (a+a \cos (c+d x))^4 \sec ^4(c+d x) \tan (c+d x)}{5 d} \]
a^4*C*x+1/8*a^4*(28*A+35*B+48*C)*arctanh(sin(d*x+c))/d+1/8*a^4*(28*A+35*B+ 40*C)*tan(d*x+c)/d+1/24*(28*A+35*B+32*C)*(a^4+a^4*cos(d*x+c))*sec(d*x+c)*t an(d*x+c)/d+1/60*(28*A+35*B+20*C)*(a^2+a^2*cos(d*x+c))^2*sec(d*x+c)^2*tan( d*x+c)/d+1/20*a*(4*A+5*B)*(a+a*cos(d*x+c))^3*sec(d*x+c)^3*tan(d*x+c)/d+1/5 *A*(a+a*cos(d*x+c))^4*sec(d*x+c)^4*tan(d*x+c)/d
Time = 6.03 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.52 \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=\frac {a^4 \left (120 C d x+15 (28 A+35 B+48 C) \text {arctanh}(\sin (c+d x))+15 \left (8 (8 A+8 B+7 C)+(28 A+27 B+16 C) \sec (c+d x)+2 (4 A+B) \sec ^3(c+d x)\right ) \tan (c+d x)+40 (8 A+4 B+C) \tan ^3(c+d x)+24 A \tan ^5(c+d x)\right )}{120 d} \]
(a^4*(120*C*d*x + 15*(28*A + 35*B + 48*C)*ArcTanh[Sin[c + d*x]] + 15*(8*(8 *A + 8*B + 7*C) + (28*A + 27*B + 16*C)*Sec[c + d*x] + 2*(4*A + B)*Sec[c + d*x]^3)*Tan[c + d*x] + 40*(8*A + 4*B + C)*Tan[c + d*x]^3 + 24*A*Tan[c + d* x]^5))/(120*d)
Time = 1.80 (sec) , antiderivative size = 244, normalized size of antiderivative = 1.08, number of steps used = 18, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.439, Rules used = {3042, 3522, 3042, 3454, 3042, 3454, 27, 3042, 3454, 27, 3042, 3447, 3042, 3500, 3042, 3214, 3042, 4257}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \sec ^6(c+d x) (a \cos (c+d x)+a)^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \int \frac {\left (a \sin \left (c+d x+\frac {\pi }{2}\right )+a\right )^4 \left (A+B \sin \left (c+d x+\frac {\pi }{2}\right )+C \sin \left (c+d x+\frac {\pi }{2}\right )^2\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^6}dx\) |
| \(\Big \downarrow \) 3522 |
| \(\displaystyle \frac {\int (\cos (c+d x) a+a)^4 (a (4 A+5 B)+5 a C \cos (c+d x)) \sec ^5(c+d x)dx}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^4 \left (a (4 A+5 B)+5 a C \sin \left (c+d x+\frac {\pi }{2}\right )\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^5}dx}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3454 |
| \(\displaystyle \frac {\frac {1}{4} \int (\cos (c+d x) a+a)^3 \left ((28 A+35 B+20 C) a^2+20 C \cos (c+d x) a^2\right ) \sec ^4(c+d x)dx+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^3 \left ((28 A+35 B+20 C) a^2+20 C \sin \left (c+d x+\frac {\pi }{2}\right ) a^2\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^4}dx+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3454 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {1}{3} \int 5 (\cos (c+d x) a+a)^2 \left ((28 A+35 B+32 C) a^3+12 C \cos (c+d x) a^3\right ) \sec ^3(c+d x)dx+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \int (\cos (c+d x) a+a)^2 \left ((28 A+35 B+32 C) a^3+12 C \cos (c+d x) a^3\right ) \sec ^3(c+d x)dx+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right )^2 \left ((28 A+35 B+32 C) a^3+12 C \sin \left (c+d x+\frac {\pi }{2}\right ) a^3\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^3}dx+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3454 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {1}{2} \int 3 (\cos (c+d x) a+a) \left ((28 A+35 B+40 C) a^4+8 C \cos (c+d x) a^4\right ) \sec ^2(c+d x)dx+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \int (\cos (c+d x) a+a) \left ((28 A+35 B+40 C) a^4+8 C \cos (c+d x) a^4\right ) \sec ^2(c+d x)dx+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \int \frac {\left (\sin \left (c+d x+\frac {\pi }{2}\right ) a+a\right ) \left ((28 A+35 B+40 C) a^4+8 C \sin \left (c+d x+\frac {\pi }{2}\right ) a^4\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^2}dx+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3447 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \int \left (8 C \cos ^2(c+d x) a^5+(28 A+35 B+40 C) a^5+\left (8 C a^5+(28 A+35 B+40 C) a^5\right ) \cos (c+d x)\right ) \sec ^2(c+d x)dx+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \int \frac {8 C \sin \left (c+d x+\frac {\pi }{2}\right )^2 a^5+(28 A+35 B+40 C) a^5+\left (8 C a^5+(28 A+35 B+40 C) a^5\right ) \sin \left (c+d x+\frac {\pi }{2}\right )}{\sin \left (c+d x+\frac {\pi }{2}\right )^2}dx+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3500 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \left (\int \left ((28 A+35 B+48 C) a^5+8 C \cos (c+d x) a^5\right ) \sec (c+d x)dx+\frac {a^5 (28 A+35 B+40 C) \tan (c+d x)}{d}\right )+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \left (\int \frac {(28 A+35 B+48 C) a^5+8 C \sin \left (c+d x+\frac {\pi }{2}\right ) a^5}{\sin \left (c+d x+\frac {\pi }{2}\right )}dx+\frac {a^5 (28 A+35 B+40 C) \tan (c+d x)}{d}\right )+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3214 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \left (a^5 (28 A+35 B+48 C) \int \sec (c+d x)dx+\frac {a^5 (28 A+35 B+40 C) \tan (c+d x)}{d}+8 a^5 C x\right )+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \frac {\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \left (a^5 (28 A+35 B+48 C) \int \csc \left (c+d x+\frac {\pi }{2}\right )dx+\frac {a^5 (28 A+35 B+40 C) \tan (c+d x)}{d}+8 a^5 C x\right )+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )+\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
| \(\Big \downarrow \) 4257 |
| \(\displaystyle \frac {\frac {a^2 (4 A+5 B) \tan (c+d x) \sec ^3(c+d x) (a \cos (c+d x)+a)^3}{4 d}+\frac {1}{4} \left (\frac {5}{3} \left (\frac {3}{2} \left (\frac {a^5 (28 A+35 B+48 C) \text {arctanh}(\sin (c+d x))}{d}+\frac {a^5 (28 A+35 B+40 C) \tan (c+d x)}{d}+8 a^5 C x\right )+\frac {(28 A+35 B+32 C) \tan (c+d x) \sec (c+d x) \left (a^5 \cos (c+d x)+a^5\right )}{2 d}\right )+\frac {a^3 (28 A+35 B+20 C) \tan (c+d x) \sec ^2(c+d x) (a \cos (c+d x)+a)^2}{3 d}\right )}{5 a}+\frac {A \tan (c+d x) \sec ^4(c+d x) (a \cos (c+d x)+a)^4}{5 d}\) |
(A*(a + a*Cos[c + d*x])^4*Sec[c + d*x]^4*Tan[c + d*x])/(5*d) + ((a^2*(4*A + 5*B)*(a + a*Cos[c + d*x])^3*Sec[c + d*x]^3*Tan[c + d*x])/(4*d) + ((a^3*( 28*A + 35*B + 20*C)*(a + a*Cos[c + d*x])^2*Sec[c + d*x]^2*Tan[c + d*x])/(3 *d) + (5*(((28*A + 35*B + 32*C)*(a^5 + a^5*Cos[c + d*x])*Sec[c + d*x]*Tan[ c + d*x])/(2*d) + (3*(8*a^5*C*x + (a^5*(28*A + 35*B + 48*C)*ArcTanh[Sin[c + d*x]])/d + (a^5*(28*A + 35*B + 40*C)*Tan[c + d*x])/d))/2))/3)/4)/(5*a)
3.4.36.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])/((c_.) + (d_.)*sin[(e_.) + (f_. )*(x_)]), x_Symbol] :> Simp[b*(x/d), x] - Simp[(b*c - a*d)/d Int[1/(c + d *Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d, 0]
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Int[(a + b*Sin[e + f*x])^m*(A*c + (B*c + A*d)*Sin[e + f*x] + B*d*Sin[e + f*x]^2), x] /; FreeQ[{a, b, c, d, e, f, A, B, m}, x] && NeQ[b*c - a*d, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Sim p[(-b^2)*(B*c - A*d)*Cos[e + f*x]*(a + b*Sin[e + f*x])^(m - 1)*((c + d*Sin[ e + f*x])^(n + 1)/(d*f*(n + 1)*(b*c + a*d))), x] - Simp[b/(d*(n + 1)*(b*c + a*d)) Int[(a + b*Sin[e + f*x])^(m - 1)*(c + d*Sin[e + f*x])^(n + 1)*Simp [a*A*d*(m - n - 2) - B*(a*c*(m - 1) + b*d*(n + 1)) - (A*b*d*(m + n + 1) - B *(b*c*m - a*d*(n + 1)))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f , A, B}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && GtQ[m, 1/2] && LtQ[n, -1] && IntegerQ[2*m] && (IntegerQ[2*n] || EqQ[c, 0 ])
Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(A*b^2 - a*b*B + a^2*C))*Cos[e + f*x]*((a + b*Sin[e + f*x])^(m + 1)/(b*f*(m + 1)* (a^2 - b^2))), x] + Simp[1/(b*(m + 1)*(a^2 - b^2)) Int[(a + b*Sin[e + f*x ])^(m + 1)*Simp[b*(a*A - b*B + a*C)*(m + 1) - (A*b^2 - a*b*B + a^2*C + b*(A *b - a*B + b*C)*(m + 1))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, e, f, A, B, C}, x] && LtQ[m, -1] && NeQ[a^2 - b^2, 0]
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)] + (C_.)*sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-(c^2*C - B*c*d + A*d^2))*Cos[e + f*x ]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(n + 1)/(d*f*(n + 1)*(c^2 - d^2))), x] + Simp[1/(b*d*(n + 1)*(c^2 - d^2)) Int[(a + b*Sin[e + f*x])^m* (c + d*Sin[e + f*x])^(n + 1)*Simp[A*d*(a*d*m + b*c*(n + 1)) + (c*C - B*d)*( a*c*m + b*d*(n + 1)) + b*(d*(B*c - A*d)*(m + n + 2) - C*(c^2*(m + 1) + d^2* (n + 1)))*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, m}, x] && NeQ[b*c - a*d, 0] && EqQ[a^2 - b^2, 0] && NeQ[c^2 - d^2, 0] && !LtQ [m, -2^(-1)] && (LtQ[n, -1] || EqQ[m + n + 2, 0])
Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]
Time = 10.42 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.18
| method | result | size |
| parts | \(-\frac {a^{4} A \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (d x +c \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (d x +c \right )\right )}{15}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (4 a^{4} A +B \,a^{4}\right ) \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )}{d}+\frac {\left (B \,a^{4}+4 C \,a^{4}\right ) \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {\left (a^{4} A +4 B \,a^{4}+6 C \,a^{4}\right ) \tan \left (d x +c \right )}{d}+\frac {\left (4 a^{4} A +6 B \,a^{4}+4 C \,a^{4}\right ) \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}-\frac {\left (6 a^{4} A +4 B \,a^{4}+C \,a^{4}\right ) \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}+\frac {C \,a^{4} \left (d x +c \right )}{d}\) | \(265\) |
| parallelrisch | \(-\frac {7 a^{4} \left (\left (A +\frac {5 B}{4}+\frac {12 C}{7}\right ) \left (\cos \left (5 d x +5 c \right )+5 \cos \left (3 d x +3 c \right )+10 \cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-\left (A +\frac {5 B}{4}+\frac {12 C}{7}\right ) \left (\cos \left (5 d x +5 c \right )+5 \cos \left (3 d x +3 c \right )+10 \cos \left (d x +c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )-\frac {10 d x C \cos \left (3 d x +3 c \right )}{7}-\frac {2 d x C \cos \left (5 d x +5 c \right )}{7}+\frac {\left (-16 C -44 A -31 B \right ) \sin \left (2 d x +2 c \right )}{7}+\frac {2 \left (-11 A -\frac {76 B}{7}-\frac {64 C}{7}\right ) \sin \left (3 d x +3 c \right )}{3}+\left (-2 A -\frac {27 B}{14}-\frac {8 C}{7}\right ) \sin \left (4 d x +4 c \right )+\frac {2 \left (-\frac {83 A}{5}-20 B -20 C \right ) \sin \left (5 d x +5 c \right )}{21}-\frac {20 d x C \cos \left (d x +c \right )}{7}-\frac {20 \left (\frac {4 B}{5}+\frac {22 C}{35}+A \right ) \sin \left (d x +c \right )}{3}\right )}{2 d \left (\cos \left (5 d x +5 c \right )+5 \cos \left (3 d x +3 c \right )+10 \cos \left (d x +c \right )\right )}\) | \(280\) |
| derivativedivides | \(\frac {a^{4} A \tan \left (d x +c \right )+B \,a^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+C \,a^{4} \left (d x +c \right )+4 a^{4} A \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 B \,a^{4} \tan \left (d x +c \right )+4 C \,a^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )-6 a^{4} A \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+6 B \,a^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+6 C \,a^{4} \tan \left (d x +c \right )+4 a^{4} A \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 B \,a^{4} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+4 C \,a^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-a^{4} A \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (d x +c \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (d x +c \right )\right )}{15}\right ) \tan \left (d x +c \right )+B \,a^{4} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-C \,a^{4} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(406\) |
| default | \(\frac {a^{4} A \tan \left (d x +c \right )+B \,a^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+C \,a^{4} \left (d x +c \right )+4 a^{4} A \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+4 B \,a^{4} \tan \left (d x +c \right )+4 C \,a^{4} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )-6 a^{4} A \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+6 B \,a^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )+6 C \,a^{4} \tan \left (d x +c \right )+4 a^{4} A \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-4 B \,a^{4} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )+4 C \,a^{4} \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )-a^{4} A \left (-\frac {8}{15}-\frac {\left (\sec ^{4}\left (d x +c \right )\right )}{5}-\frac {4 \left (\sec ^{2}\left (d x +c \right )\right )}{15}\right ) \tan \left (d x +c \right )+B \,a^{4} \left (-\left (-\frac {\left (\sec ^{3}\left (d x +c \right )\right )}{4}-\frac {3 \sec \left (d x +c \right )}{8}\right ) \tan \left (d x +c \right )+\frac {3 \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{8}\right )-C \,a^{4} \left (-\frac {2}{3}-\frac {\left (\sec ^{2}\left (d x +c \right )\right )}{3}\right ) \tan \left (d x +c \right )}{d}\) | \(406\) |
| risch | \(a^{4} C x -\frac {i a^{4} \left (-120 A \,{\mathrm e}^{8 i \left (d x +c \right )}-800 C -664 A -800 B -4720 A \,{\mathrm e}^{4 i \left (d x +c \right )}-5120 B \,{\mathrm e}^{4 i \left (d x +c \right )}-3520 B \,{\mathrm e}^{2 i \left (d x +c \right )}-4880 C \,{\mathrm e}^{4 i \left (d x +c \right )}-3280 C \,{\mathrm e}^{2 i \left (d x +c \right )}+930 B \,{\mathrm e}^{7 i \left (d x +c \right )}-1320 A \,{\mathrm e}^{3 i \left (d x +c \right )}-3200 A \,{\mathrm e}^{2 i \left (d x +c \right )}-420 A \,{\mathrm e}^{i \left (d x +c \right )}-405 B \,{\mathrm e}^{i \left (d x +c \right )}-2880 B \,{\mathrm e}^{6 i \left (d x +c \right )}-930 B \,{\mathrm e}^{3 i \left (d x +c \right )}-1920 A \,{\mathrm e}^{6 i \left (d x +c \right )}-3120 C \,{\mathrm e}^{6 i \left (d x +c \right )}+1320 A \,{\mathrm e}^{7 i \left (d x +c \right )}-240 C \,{\mathrm e}^{i \left (d x +c \right )}-480 B \,{\mathrm e}^{8 i \left (d x +c \right )}+480 C \,{\mathrm e}^{7 i \left (d x +c \right )}-480 C \,{\mathrm e}^{3 i \left (d x +c \right )}-720 C \,{\mathrm e}^{8 i \left (d x +c \right )}+240 C \,{\mathrm e}^{9 i \left (d x +c \right )}+420 A \,{\mathrm e}^{9 i \left (d x +c \right )}+405 B \,{\mathrm e}^{9 i \left (d x +c \right )}\right )}{60 d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{5}}+\frac {7 a^{4} A \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{2 d}+\frac {35 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) B}{8 d}+\frac {6 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) C}{d}-\frac {7 a^{4} A \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{2 d}-\frac {35 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) B}{8 d}-\frac {6 a^{4} \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) C}{d}\) | \(460\) |
-a^4*A/d*(-8/15-1/5*sec(d*x+c)^4-4/15*sec(d*x+c)^2)*tan(d*x+c)+(4*A*a^4+B* a^4)/d*(-(-1/4*sec(d*x+c)^3-3/8*sec(d*x+c))*tan(d*x+c)+3/8*ln(sec(d*x+c)+t an(d*x+c)))+(B*a^4+4*C*a^4)/d*ln(sec(d*x+c)+tan(d*x+c))+(A*a^4+4*B*a^4+6*C *a^4)/d*tan(d*x+c)+(4*A*a^4+6*B*a^4+4*C*a^4)/d*(1/2*sec(d*x+c)*tan(d*x+c)+ 1/2*ln(sec(d*x+c)+tan(d*x+c)))-(6*A*a^4+4*B*a^4+C*a^4)/d*(-2/3-1/3*sec(d*x +c)^2)*tan(d*x+c)+C*a^4/d*(d*x+c)
Time = 0.29 (sec) , antiderivative size = 196, normalized size of antiderivative = 0.87 \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=\frac {240 \, C a^{4} d x \cos \left (d x + c\right )^{5} + 15 \, {\left (28 \, A + 35 \, B + 48 \, C\right )} a^{4} \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \, {\left (28 \, A + 35 \, B + 48 \, C\right )} a^{4} \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (8 \, {\left (83 \, A + 100 \, B + 100 \, C\right )} a^{4} \cos \left (d x + c\right )^{4} + 15 \, {\left (28 \, A + 27 \, B + 16 \, C\right )} a^{4} \cos \left (d x + c\right )^{3} + 8 \, {\left (34 \, A + 20 \, B + 5 \, C\right )} a^{4} \cos \left (d x + c\right )^{2} + 30 \, {\left (4 \, A + B\right )} a^{4} \cos \left (d x + c\right ) + 24 \, A a^{4}\right )} \sin \left (d x + c\right )}{240 \, d \cos \left (d x + c\right )^{5}} \]
integrate((a+a*cos(d*x+c))^4*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^6, x, algorithm="fricas")
1/240*(240*C*a^4*d*x*cos(d*x + c)^5 + 15*(28*A + 35*B + 48*C)*a^4*cos(d*x + c)^5*log(sin(d*x + c) + 1) - 15*(28*A + 35*B + 48*C)*a^4*cos(d*x + c)^5* log(-sin(d*x + c) + 1) + 2*(8*(83*A + 100*B + 100*C)*a^4*cos(d*x + c)^4 + 15*(28*A + 27*B + 16*C)*a^4*cos(d*x + c)^3 + 8*(34*A + 20*B + 5*C)*a^4*cos (d*x + c)^2 + 30*(4*A + B)*a^4*cos(d*x + c) + 24*A*a^4)*sin(d*x + c))/(d*c os(d*x + c)^5)
Timed out. \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=\text {Timed out} \]
Leaf count of result is larger than twice the leaf count of optimal. 496 vs. \(2 (213) = 426\).
Time = 0.22 (sec) , antiderivative size = 496, normalized size of antiderivative = 2.20 \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=\frac {16 \, {\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} A a^{4} + 480 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} A a^{4} + 320 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B a^{4} + 80 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a^{4} + 240 \, {\left (d x + c\right )} C a^{4} - 60 \, A a^{4} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 15 \, B a^{4} {\left (\frac {2 \, {\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 240 \, A a^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 360 \, B a^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 240 \, C a^{4} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 120 \, B a^{4} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 480 \, C a^{4} {\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 240 \, A a^{4} \tan \left (d x + c\right ) + 960 \, B a^{4} \tan \left (d x + c\right ) + 1440 \, C a^{4} \tan \left (d x + c\right )}{240 \, d} \]
integrate((a+a*cos(d*x+c))^4*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^6, x, algorithm="maxima")
1/240*(16*(3*tan(d*x + c)^5 + 10*tan(d*x + c)^3 + 15*tan(d*x + c))*A*a^4 + 480*(tan(d*x + c)^3 + 3*tan(d*x + c))*A*a^4 + 320*(tan(d*x + c)^3 + 3*tan (d*x + c))*B*a^4 + 80*(tan(d*x + c)^3 + 3*tan(d*x + c))*C*a^4 + 240*(d*x + c)*C*a^4 - 60*A*a^4*(2*(3*sin(d*x + c)^3 - 5*sin(d*x + c))/(sin(d*x + c)^ 4 - 2*sin(d*x + c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin(d*x + c) - 1)) - 15*B*a^4*(2*(3*sin(d*x + c)^3 - 5*sin(d*x + c))/(sin(d*x + c)^4 - 2 *sin(d*x + c)^2 + 1) - 3*log(sin(d*x + c) + 1) + 3*log(sin(d*x + c) - 1)) - 240*A*a^4*(2*sin(d*x + c)/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) - 360*B*a^4*(2*sin(d*x + c)/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) - 240*C*a^4*(2*sin(d*x + c )/(sin(d*x + c)^2 - 1) - log(sin(d*x + c) + 1) + log(sin(d*x + c) - 1)) + 120*B*a^4*(log(sin(d*x + c) + 1) - log(sin(d*x + c) - 1)) + 480*C*a^4*(log (sin(d*x + c) + 1) - log(sin(d*x + c) - 1)) + 240*A*a^4*tan(d*x + c) + 960 *B*a^4*tan(d*x + c) + 1440*C*a^4*tan(d*x + c))/d
Time = 0.39 (sec) , antiderivative size = 352, normalized size of antiderivative = 1.56 \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=\frac {120 \, {\left (d x + c\right )} C a^{4} + 15 \, {\left (28 \, A a^{4} + 35 \, B a^{4} + 48 \, C a^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 15 \, {\left (28 \, A a^{4} + 35 \, B a^{4} + 48 \, C a^{4}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (420 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 525 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 600 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} - 1960 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 2450 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 2720 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 3584 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 4480 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 4720 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3160 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 3950 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 3680 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 1500 \, A a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1395 \, B a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1080 \, C a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{5}}}{120 \, d} \]
integrate((a+a*cos(d*x+c))^4*(A+B*cos(d*x+c)+C*cos(d*x+c)^2)*sec(d*x+c)^6, x, algorithm="giac")
1/120*(120*(d*x + c)*C*a^4 + 15*(28*A*a^4 + 35*B*a^4 + 48*C*a^4)*log(abs(t an(1/2*d*x + 1/2*c) + 1)) - 15*(28*A*a^4 + 35*B*a^4 + 48*C*a^4)*log(abs(ta n(1/2*d*x + 1/2*c) - 1)) - 2*(420*A*a^4*tan(1/2*d*x + 1/2*c)^9 + 525*B*a^4 *tan(1/2*d*x + 1/2*c)^9 + 600*C*a^4*tan(1/2*d*x + 1/2*c)^9 - 1960*A*a^4*ta n(1/2*d*x + 1/2*c)^7 - 2450*B*a^4*tan(1/2*d*x + 1/2*c)^7 - 2720*C*a^4*tan( 1/2*d*x + 1/2*c)^7 + 3584*A*a^4*tan(1/2*d*x + 1/2*c)^5 + 4480*B*a^4*tan(1/ 2*d*x + 1/2*c)^5 + 4720*C*a^4*tan(1/2*d*x + 1/2*c)^5 - 3160*A*a^4*tan(1/2* d*x + 1/2*c)^3 - 3950*B*a^4*tan(1/2*d*x + 1/2*c)^3 - 3680*C*a^4*tan(1/2*d* x + 1/2*c)^3 + 1500*A*a^4*tan(1/2*d*x + 1/2*c) + 1395*B*a^4*tan(1/2*d*x + 1/2*c) + 1080*C*a^4*tan(1/2*d*x + 1/2*c))/(tan(1/2*d*x + 1/2*c)^2 - 1)^5)/ d
Time = 3.13 (sec) , antiderivative size = 995, normalized size of antiderivative = 4.42 \[ \int (a+a \cos (c+d x))^4 \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx=\text {Too large to display} \]
((11*A*a^4*sin(2*c + 2*d*x))/8 + (77*A*a^4*sin(3*c + 3*d*x))/48 + (7*A*a^4 *sin(4*c + 4*d*x))/16 + (83*A*a^4*sin(5*c + 5*d*x))/240 + (31*B*a^4*sin(2* c + 2*d*x))/32 + (19*B*a^4*sin(3*c + 3*d*x))/12 + (27*B*a^4*sin(4*c + 4*d* x))/64 + (5*B*a^4*sin(5*c + 5*d*x))/12 + (C*a^4*sin(2*c + 2*d*x))/2 + (4*C *a^4*sin(3*c + 3*d*x))/3 + (C*a^4*sin(4*c + 4*d*x))/4 + (5*C*a^4*sin(5*c + 5*d*x))/12 + (35*A*a^4*sin(c + d*x))/24 + (7*B*a^4*sin(c + d*x))/6 + (11* C*a^4*sin(c + d*x))/12 + (5*C*a^4*atan((784*A^2*sin(c/2 + (d*x)/2) + 1225* B^2*sin(c/2 + (d*x)/2) + 2368*C^2*sin(c/2 + (d*x)/2) + 1960*A*B*sin(c/2 + (d*x)/2) + 2688*A*C*sin(c/2 + (d*x)/2) + 3360*B*C*sin(c/2 + (d*x)/2))/(cos (c/2 + (d*x)/2)*(784*A^2 + 1225*B^2 + 2368*C^2 + 1960*A*B + 2688*A*C + 336 0*B*C)))*cos(c + d*x))/4 + (5*C*a^4*atan((784*A^2*sin(c/2 + (d*x)/2) + 122 5*B^2*sin(c/2 + (d*x)/2) + 2368*C^2*sin(c/2 + (d*x)/2) + 1960*A*B*sin(c/2 + (d*x)/2) + 2688*A*C*sin(c/2 + (d*x)/2) + 3360*B*C*sin(c/2 + (d*x)/2))/(c os(c/2 + (d*x)/2)*(784*A^2 + 1225*B^2 + 2368*C^2 + 1960*A*B + 2688*A*C + 3 360*B*C)))*cos(3*c + 3*d*x))/8 + (C*a^4*atan((784*A^2*sin(c/2 + (d*x)/2) + 1225*B^2*sin(c/2 + (d*x)/2) + 2368*C^2*sin(c/2 + (d*x)/2) + 1960*A*B*sin( c/2 + (d*x)/2) + 2688*A*C*sin(c/2 + (d*x)/2) + 3360*B*C*sin(c/2 + (d*x)/2) )/(cos(c/2 + (d*x)/2)*(784*A^2 + 1225*B^2 + 2368*C^2 + 1960*A*B + 2688*A*C + 3360*B*C)))*cos(5*c + 5*d*x))/8 + (35*A*a^4*cos(c + d*x)*atanh(sin(c/2 + (d*x)/2)/cos(c/2 + (d*x)/2)))/8 + (175*B*a^4*cos(c + d*x)*atanh(sin(c...